SOLUTION: log(x-1)+log(x+2)=log(14)
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Question 239430: log(x-1)+log(x+2)=log(14)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The sum of the logs is the log of the product, so:
\ +\ \log(x+2)\ =\ \log(14))
\ =\ \log(14))
Since we know:
\ =\ \log_b(\beta)\ \Leftrightarrow\ \ \alpha\ =\ \beta)
Just solve the quadratic. Since the domain of the logarithm function is all real numbers greater than zero, you must exclude any root less than or equal to 1. The explanation of why is left as an additional exercise for the student.
John
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