SOLUTION: can u please explain the logarithm 3log2x-log2x=8? by the way the log has a base of 2. the book said that the answer was 8.1 but i dont understand how they got that. this is wat i

Algebra ->  Algebra  -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: can u please explain the logarithm 3log2x-log2x=8? by the way the log has a base of 2. the book said that the answer was 8.1 but i dont understand how they got that. this is wat i       Log On

Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 235627: can u please explain the logarithm 3log2x-log2x=8? by the way the log has a base of 2. the book said that the answer was 8.1 but i dont understand how they got that. this is wat i did:
3log2x-log2x=8





and thats as far as i got
Answer by Alan3354(6097) About Me  (Show Source):
You can put this solution on YOUR website!
3log2x-log2x=8




and thats as far as i got

x = ±16
Since it's inside the log function, the -16 is rejected.
--------
You were almost there.
I don't see how it can be 8, unless there's a typo.