# SOLUTION: The half-life of a certain radioactive substance is 15 years. Suppose that at time t = 0, there are 29 g of the substance. Then after t years, the number of grams of the substa

Algebra ->  Algebra  -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: The half-life of a certain radioactive substance is 15 years. Suppose that at time t = 0, there are 29 g of the substance. Then after t years, the number of grams of the substa      Log On

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 Question 235145: The half-life of a certain radioactive substance is 15 years. Suppose that at time t = 0, there are 29 g of the substance. Then after t years, the number of grams of the substance remaining will be How many grams of the substance will remain after 45 years? Answer by ankor@dixie-net.com(15665)   (Show Source): You can put this solution on YOUR website!The half life formula A = Ao(2^(-t/h)) Where A = resulting amt after t yrs Ao = initial amt h = half-life of substance : The half-life of a certain radioactive substance is 15 years. Suppose that at time t = 0, there are 29 g of the substance. Then after t years, the number of grams of the substance remaining will be: A = 29(2^(-t/15)) : How many grams of the substance will remain after 45 years? A = 29(2^(-45/15)) A = 29(2^-3) A = 29*.125 A = 3.625 grams