SOLUTION: I am having a hard time of this question i would really appreciate the help.
Solve for x: log(x-2)+ log x = log 3
I just don't do how to put all togther.
Thank you!!!!!
Algebra.Com
Question 224352: I am having a hard time of this question i would really appreciate the help.
Solve for x: log(x-2)+ log x = log 3
I just don't do how to put all togther.
Thank you!!!!!
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The sum of the logs is the log of the product:
 + \log_b(y) = \log_b(xy))
So:
\ +\ \log(x)\ =\ \log(x(x-2))\ =\ log(x^2-2x)\ =\ \log(3))
If two logs to the same base (here, understood base 10) are equal then their arguments must be equal:
\ =\ log_b(y)\ \Leftrightarrow\ x\ = \ y)
Hence:
Just solve your quadratic. Check BOTH roots for extraneous values considering the domain of the log function.
John
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