SOLUTION: log 16/log 32

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Question 223055: log 16/log 32
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
There's a couple of ways to solve this:
  1. Recognize that this is an example of the base conversion formula for logarithms, log%28a%2C+%28x%29%29+=+log%28b%2C+%28x%29%29%2Flog%28b%2C+%28a%29%29 with a = 32 and b = 10. So log%28%2816%29%29%2Flog%28%2832%29%29+=+log%2832%2C+%2816%29%29. Let's call the later log "x": x+=+log%2832%2C+%2816%29%29. Now let's rewrite this in exponential form: 32%5Ex+=+16. Next, since both 32 and 16 are both powers of 2, we'll rewrite them this way so we can have the same base: %282%5E5%29%5Ex+=+2%5E4. Using a rule for exponents on the left: 2%5E%285x%29+=+2%5E4. This tells us that 5x = 4 or x = 4/5.
  2. Let x+=+log%28%2816%29%29%2Flog%28%2832%29%29. Multiply both sides by log%28%2832%29%29: x%2Alog%28%2832%29%29+=+log%28%2816%29%29. Using a rule for logarithms we can "move" the x from in front into the argument as an exponent: log%28%2832%5Ex%29%29+=+log%28%2816%29%29. Since the log of 32%5Ex equals the log of 16, 32%5Ex+=+16. (We reached the same equation above, via a different route. The rest of the solution is the same.)

So, either way, log%28%2816%29%29%2Flog%28%2832%29%29+=+4%2F5.