You can
put this solution on YOUR website!A ball is thrown into the air its velocity is 45ft/s its height in feet after t sec is given by 45t-19t^2. Find the instantaneous velocity when t=2
Step 1. Let height = h =
where velocity is 45 ft/s
Step 2. Derivative of h = velocity = 45 - 36t.
Step 3. Substitute t=2 into Step 2. velocity = 45 -36(2)= 45 - 72 = -27 ft/s
Step 4. Since velocity is negative it is heading down at 27 ft/s.
I hope the above steps were helpful.
And good luck in your studies!
Respectfully,
Dr J
For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra.
You can
put this solution on YOUR website!a ball is thrown into the air its velocity is 45ft/s its height in freet after t sec is given by 45t-19t^2. Find the instaneous velocity when t=2
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If you are studying calculus, evaluate the derivative at t = 2.
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If h(t) = -19t^2+45t
then h'(t) = -38t+45
and h'(2) = -38(2)+45 = -76+45 = -31
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Cheers,
Stan H.
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