SOLUTION: I need help with the problem {{{e^(2x+1)=9e^(1-x)}}} The question says to solve for the missing variable. SO what i did was made both sides in terms of e and then set the exponents

Question 210767This question is from textbook Single Variable Calculus
: I need help with the problem The question says to solve for the missing variable. SO what i did was made both sides in terms of e and then set the exponents equal to each other and i get 8/11 which i am told is not correct. help please? This question is from textbook Single Variable Calculus

Found 2 solutions by stanbon, tutor_paul:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
e^(2x+1)=9e^(1-x)
------------------------
Take the natural log of both sides:
---
2x+1 = ln(9) + (1-x)
3x = ln(9)
x = [ln(9)]/3
x = 0.7324..
Cheers,
Stan H.
Answer by tutor_paul(519) (Show Source): You can put this solution on YOUR website!

Take the natural log of both sides:

use properties of logarithms:

solve for x:

============
Good Luck,
tutor_paul@yahoo.com
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