SOLUTION: I need major help on logarithms. if i have: ln(x-2)+ ln(2x-3)= 2lnx i know that im supposed to have ln((x-2)(2x-3))=lnx^2 which would eliminate the ln but what do i

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Question 209708: I need major help on logarithms.
if i have:
ln(x-2)+ ln(2x-3)= 2lnx
i know that im supposed to
have
ln((x-2)(2x-3))=lnx^2
which would eliminate the ln
but what do i do afterwards?

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
ln(x-2)+ ln(2x-3)= 2lnx
ln((x-2)(2x-3))=lnx^2
(x-2)(2x-3) = x^2
2x^2 - 7x + 6 = x^2
x^2 - 7x + 6 = 0
(x-1)*(x-6) = 0
x = 1 This won't work as ln(1-2) is not allowed.
x = 6

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