SOLUTION: log(5)^(x)-log(5)^(x-20)=1 log(2)^(x)+5=8-log(2)^(x+7) I need help with finding the answer and the steps to getting the answer.

Algebra.Com
Question 207833: log(5)^(x)-log(5)^(x-20)=1
log(2)^(x)+5=8-log(2)^(x+7)
I need help with finding the answer and the steps to getting the answer.

Answer by dlam5(15)   (Show Source): You can put this solution on YOUR website!
For
Take log(5)^x; by logarithm properties, take the x out of the exponent, which is...
x log(5) ;
Now, take log(5)^(x-20); and do the same DISTRIBUTIVE property of log by taking...

(x-20) log 5; now distribute the log 5 for x and 20; this then cleans up to be...
xlog5 - 20log5.
Your equation should come out to be xlog5 - xlog5 -20log5 =1.
But, look closely; XLOG5 - XLOG5= 0; so x doesn;t have an answer as a variable.
Therfore, this equation is the EMPTY SET (undefined).
Try the next one in the same manner, and e-mail me if you need any help.
Thanks,
dlam5 :)

RELATED QUESTIONS

Find the exact solution 8^(x-1)=16^(x+3) I keep getting 3 log(2^x-1)=4 log(2^x+3)... (answered by stanbon,solver91311)
Kindly help me answer these items/how to answer them: I. Solve the ff. equations.... (answered by jsmallt9)
help me solve 5^x = 7*3^x the answer the teacher gives is x =... (answered by user_dude2008)
log(x)=log(3)+log(x-6) log(X)+log(x-5)=log(6) I really need help with this 2... (answered by stanbon)
I don't even know where to start with this one, looking for help Solve for x 27.)... (answered by ankor@dixie-net.com)
2 log (1-x) = log (x+5) + log... (answered by josgarithmetic)
Solve for x log(base5)x+log(base5)(x+1)=7 I tried solving this equation but couldn't... (answered by josgarithmetic,Boreal)
log base 5 (log base 2 x) = 1 what are the steps to solve... (answered by Earlsdon)
log(3x)= log 5 +... (answered by drk)