SOLUTION: What is the value of X in this equation? log{{{7}}}X + log{{{7}}}X - log{{{7}}}3 = log{{{7}}}12 I was thinking that you could add log{{{7}}}3 to both sides of the equation. Howeve

You can put this solution on YOUR website!
log₇X + log₇X = log₇12 + log₇3
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The two terms on the left are just alike so when you add them you just get 2 of
them! That is, log<sub>7</sub>x + log<sub>7</sub>x = 2·log<sub>7</sub>x. So now you have
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2·log₇X = log₇12 + log₇3
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Use the rule N·log<sub>B</sub>U = log<sub>B</sub>U<sup>N</sup> on the left
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log₇X² = log₇12 + log₇3
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Now use the rule log<sub>B</sub>U + log<sub>B</sub>V = log<sub>B</sub>UV
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log₇X² = log₇(12·3)
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Now raise both sides to the 7 power, which is the same as dropping the logs.
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X² = 36
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X = ±6, but we cannot take logs of negative numbers, so the answer is X = 6
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Edwin
AnlytcPhil@aol.com