SOLUTION: Use log{{{10}}}5 = 0.6990 and log{{{10}}}7 = 0.8451 to evaluate log{{{10}}}490 I tried to start it but I kept getting stuck. I appreciate your help. THANKS

Question 20544: Use log5 = 0.6990 and log7 = 0.8451 to evaluate log490
I tried to start it but I kept getting stuck. I appreciate your help. THANKS
Answer by AnlytcPhil(1810) (Show Source): You can put this solution on YOUR website!
Use log(5) = 0.6990 and log(7) = 0.8451 to evaluate log(490)
I tried to start it but I kept getting stuck. I appreciate your help. THANKS
`
These ase base 10 logs, so log(10) = 1
`
Write 490 as 49�10, then as 72�10
`
log(490) = log(72�10) = log(72) + log(10) = 2�log(7) + log(10) =
`
2�0.8451 + 1 = 1.6902 + 1 = 2.6902
`
Edwin
AnlytcPhil@aol.com
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