SOLUTION: Solve. Ln(2x^2+0.5)=0

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Question 202882: Solve. Ln(2x^2+0.5)=0
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solve. Ln(2x^2+0.5)=0
2x^2+0.5 = e^0
2x^2 + 0.5 = 1
2x^2 = 1/2
x^2 = 1/4
x = 1/2 or x = -1/2
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Cheers,
Stan H.