SOLUTION: could sombody help me to solve it? 1/3.log(20,2x-1)=log(20,11)-2.log(20,(2x-1)^(1/3))+log(5,(log7,7))

Question 202664: could sombody help me to solve it?
1/3.log(20,2x-1)=log(20,11)-2.log(20,(2x-1)^(1/3))+log(5,(log7,7))
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Quick note: and . So . In other words,

So the expression

simplifies to

-----------------------------------

Start with the given expression.

Rewrite the last log using the identity

Multiply

Subtract from both sides.

Subtract from both sides.

Factor out the GCF

Combine like terms.

Reduce

Multiply both sides by -1

Since the bases of the logs are equal, this means that the arguments are equal.

Add 1 to both sides.

Combine like terms.

Divide both sides by 2 to isolate "x".

Reduce

Rearrange the equation.

==================================================================

Answer:

So the solution is

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