SOLUTION: log 5 10 = log 5 30 =
ln20 - ln5 =
2 log 3 = log 5 - log 15
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Question 200511: log 5 10 = log 5 30 =
ln20 - ln5 =
2 log 3 = log 5 - log 15
Found 2 solutions by Alan3354, solver91311:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
It isn't clear what you're trying to do, but
log 5 10 = log 5 30 = ?? No, it doesn't.
--------------
ln20 - ln5 =
= log(5/20) = log(4) + ~ 0.60206
---------------
2 log 3 = log 5 - log 15
That's not true, either. ???
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Your first problem makes no sense.  \neq \log_5(30))
. So the only answer possible is:
 = \log_5(30) =)
False, meaning the statement "the base 5 log of 10 is equal to the base 5 log of 30" is a false statement.
The difference of the logs is the log of the quotient, so:
 - \ln(5) = \ln\left(\frac{20}{5}\right) = \ln(4))
Your third problem makes no sense either. How can  = \log(3^2) =\log(9))
be equal to )
?
John
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