SOLUTION: If a^(1/3)+b^(1/3)+c^(1/3)=0, then show that log[(a+b+c)/3]=1/3[loga+logb+logc]

SOLUTION: If a^(1/3)+b^(1/3)+c^(1/3)=0, then show that log[(a+b+c)/3]=1/3[loga+logb+logc]

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Question 200367: If a^(1/3)+b^(1/3)+c^(1/3)=0, then show that log[(a+b+c)/3]=1/3[loga+logb+logc]
Answer by orca(409) (Show Source): You can put this solution on YOUR website!

cube both sides

Noting that , we have

So
log[(a+b+c)/3]=1/3[loga+logb+logc]
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