SOLUTION: {{{log3 (x-2) + log3 (x-4) = 2 }}}

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Question 199943: log3+%28x-2%29+%2B+log3+%28x-4%29+=+2+
Answer by ankor@dixie-net.com(12692) About Me  (Show Source):
You can put this solution on YOUR website!
log3+%28x-2%29+%2B+log3+%28x-4%29+=+2+
:
Addition of logs, the same as multiply
log3%28%28x-2%29%2A%28x-4%29%29+=+2+
FOIL
log3%28x%5E2-6x%2B8%29+=+2+
The exponent equiv of logs:
(x^2 - 6x + 8) = 3^2
:
x^2 - 6x + 8 = 9
:
x^2 - 6x + 8 - 9 = 0
:
x^2 - 6x - 1 = 0
:
Use the quadratic formula: a=1; b=-6; c=-1
The positive solution: x ~ 6.162
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