SOLUTION: what values of x cannot possibly be solutions of the following equation?
LOGa(3x+1)=2
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Question 199628: what values of x cannot possibly be solutions of the following equation?
LOGa(3x+1)=2
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Recall that you CANNOT evaluate the log of a negative value or 0. So this means that
Start with the given inequality.
Subtract from both sides.
Combine like terms on the right side.
Divide both sides by to isolate .
This means that any values of x that are either equal to or are less than are NOT allowed.
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