SOLUTION: Prove that 7^(n+2)-35(7^n-1)/44(7^n+2) is equal to 1/49
Algebra.Com
Question 199294: Prove that 7^(n+2)-35(7^n-1)/44(7^n+2) is equal to 1/49
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
[ 7^(n+2) -35*7^9n-1)] / [ 44(7^(n+2) ) ] = 1/49
.
[ 1-35*7^-3] / 44 = 1/49
.
[ 1 - 35 / (49*7) ] / 44 = 1/49
.
[ 1-5/49] / 44 = 1/49
.
[49/49 -5/49 ] / 44 = 1/49
.
[ 44 / 49 ] / 44 = 1/49
.
(44/49) * (1/44) = 1/49 = 1/49,,,,,,ok
RELATED QUESTIONS
[7^(n+2)-35(7^(n-1))]/44(7^(n+2)) (answered by lwsshak3)
Simplify by removing factors of 1. n^2-49/(n+7)^2 The simplified form... (answered by Fombitz)
Simplify
7^n-3×7^(n+1) /... (answered by ankor@dixie-net.com)
7(n-1)=-2(3+n) (answered by unlockmath)
Dear math teacher,
I am having difficulties with the following problem:
4 times nC2 (answered by Theo)
prove that : n! (n+2) = n! +... (answered by tommyt3rd)
log 7... (answered by jsmallt9)
simplify by removing factors of 1... (answered by checkley77)
prove that: 1+2+3+....+n =... (answered by ikleyn)