# SOLUTION: A=A 2^-t/5760 A= amount of carbon 14 that a specimen contains A= original amount of carbon 14 t=time in years 5760= half life of carbon-14 A specimen that originally contai

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 Click here to see ALL problems on logarithm Question 198180This question is from textbook Amsco Math B : A=A 2^-t/5760 A= amount of carbon 14 that a specimen contains A= original amount of carbon 14 t=time in years 5760= half life of carbon-14 A specimen that originally contained 120 milligrams of carbon-1 now contains 100 milligrams of this substance, what is the age of the specimen, to the nearest hundred years? This question is from textbook Amsco Math B Answer by stanbon(57347)   (Show Source): You can put this solution on YOUR website!A(t) = Ao 2^(-t/5760) A= amount of carbon 14 that a specimen contains A= original amount of carbon 14 t=time in years 5760= half life of carbon-14 ---------------------------------------- A specimen that originally contained 120 milligrams of carbon-1 now contains 100 milligrams of this substance, what is the age of the specimen, to the nearest hundred years? --- 100 = 120*2^(-t/5760) (5/6) = 2^(-t/576)0 Take the log to get: (-t/5760)log(2) = log(5/6) -t/5760 = -0.263034 t = 1515.078 year t = 1500 years when rounded to the nearest 100 ==================== Cheers, Stan H.