SOLUTION: How do you solve log(2x+3)-logx=1
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Question 198151: How do you solve log(2x+3)-logx=1
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How do you solve log(2x+3)-logx=1
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log[(2x+3)/x] = 1
(2x+3)/x = 10^1
2x+3 = 10x
8x = 3
x = 3/8
=================
Cheers,
Stan H.
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