SOLUTION: what is log2(x-2) +log2 (x+2) = 5? Thank you.
Algebra.Com
Question 195202: what is log2(x-2) +log2 (x+2) = 5? Thank you.
Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
all logs are base 2
log2 (x-2) +log2 (x+2) = 5
log2[ (x-2)(x+2) ] = 5
(x-2)(x+2) = 2^5
(x-2)(x+2) = 32
x^2-4 = 32
x^2 = 36
x = -6 (extraneous) or x = 6
Ans: only solution is x = 6
RELATED QUESTIONS
log2(x+2)+log2(x-2)=5 (answered by robertb)
log2(x+2)+log2(x-2)=5 (answered by ankor@dixie-net.com)
Log2 (x+2) = log2 3-log2... (answered by Alan3354,MathTherapy)
log2(x - 2) + 5 = 8 - log2... (answered by mukhopadhyay)
log2(x - 2) + 5 = 8 - log2... (answered by Nate)
log2(x - 2) + 5 = 8 - log2... (answered by jim_thompson5910)
log2(3x-2)-log2(x-5)=4 (answered by robertb)
Solve: Log2(2) +log2(x+3)=5 (answered by stanbon)
5 log2 (2 x – 3) = log2 (2 x – 3) + 12, what is the value of... (answered by lwsshak3)