SOLUTION: log3 64-log3 8/3+ log3 2=log3 4r

Question 194552: log3 64-log3 8/3+ log3 2=log3 4r
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
log(3) 64 -log(3) 8/3 + log(3) 2 = log(3) 4R
log (3) [ { 64 *2} / (8/3) ] = log (3) 4R
log(3) (48) = log(3) 4R
48 = 4 R
R = 12,,,,,,,,ANSWER
,
checking
log 64/log3 -log(8/3)/log3 +log2//og3 = log 48/log 3
1.68 = 1.68 ,,,,,,ok
RELATED QUESTIONS
log3(x-2)+log3(x-8)=3 (answered by josgarithmetic)

Log3(x+1)-log3(x)+log3(3) (answered by Alan3354)

solve 2 log3)=log3) (4)+ log3)... (answered by Alan3354)

Log3(3x+8)=log3(x^2+x) (answered by ewatrrr)

solve:... (answered by nerdybill)

solve log3(x-3) + log3(x+2) = log3... (answered by rothauserc)

log3(x) +... (answered by stanbon)

log3 (x+3) + log3 (x-7)... (answered by longjonsilver)

log3(x-2)+log3(x+4)=3 (answered by nerdybill)