SOLUTION: log(x+1)+log(x-2)=1

Question 193653: log(x+1)+log(x-2)=1
Found 2 solutions by Alan3354, josmiceli:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
log(x+1)+log(x-2)=1
------------
log((x+1)*(x-2)) = 1
(x+1)*(x-2) = 10

(x-4)*(x+3) = 0
x = 4
x = -3

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
In general:
so,

also,

If the logs are equal, the antilogs are equal

this result doesn't work, becase it
gives me a and no log can give a
negative answer
check:

(inaccuracy is due to rounding off)
OK

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