SOLUTION: log4(x)+log4(x-6)=2

Question 193652: log4(x)+log4(x-6)=2
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
log4(x)+log4(x-6)=2
log4((x)(x-6))=2
(x)(x-6)=4^2
(x)(x-6)=16
x^2-6x=16
x^2-6x-16=0
(x-8)(x+2) = 0
.
x = {-2, 8}
Throw out the negative solution (can't have log of negatives):
x = 8

RELATED QUESTIONS
Solve for x: log4^8 + log4^6 =... (answered by Nate)

log4^2 + log4^8 =... (answered by ankor@dixie-net.com)

log4(2)−log4(x)=log4(3) (answered by jim_thompson5910)

solve: log4 (x-6) =... (answered by )

solve: log4 (x-6) =... (answered by mudassirhussain,ILAxbaseballx720)

log4x+log4(x-6)=2 (answered by lwsshak3)

how to solve... (answered by stanbon)

Solve for x Log4^x+... (answered by solver91311)

log4 x-log4 (x+3)+log4... (answered by ewatrrr)