SOLUTION: if $350 is deposited in an account paying 2% annual interest, compunded continuously, how long will it take for the account to increase to $1500?
A=Pe^rt
1500=350e^.02(t)
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Question 193252: if $350 is deposited in an account paying 2% annual interest, compunded continuously, how long will it take for the account to increase to $1500?
A=Pe^rt
1500=350e^.02(t)
then im lost...
Found 2 solutions by MathGuyJoe, jim_thompson5910:
Answer by MathGuyJoe(20) (Show Source): You can put this solution on YOUR website!
To Solve:
You must first isolate the e^x component -- so divide both sides by 350:
Simplifying gives you:
Next, take the natural log (ln) of both sides:
Now, use the power rule to simplify the right side:
Since , you're left with:
Divide both sides by .02 to get:
So t = 72.76 years
Hope this helps.
~ Joe
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation.
Plug in A=1500, P=350, and r=0.02
Divide both sides by 350.
Divide
Take the natural log of both sides (to eliminate the base "e")
Evaluate the natural log of 4.2857
Divide both sides by 0.02
Divide
Rearrange the equation
So it will take approximately 72.765 years for $350 to grow into $1,500.
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