SOLUTION: Given f(x) = e^-2x + 1, evaluate the following. Round to the nearest ten-thousandth.
f(-1)
f(3)
f(-2)
Show your work here:
f(-1)=e -2(-1)+1=x-1
f(-1)=e^2+1
f(-1)=7.389
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Question 191051This question is from textbook
: Given f(x) = e^-2x + 1, evaluate the following. Round to the nearest ten-thousandth.
f(-1)
f(3)
f(-2)
Show your work here:
f(-1)=e -2(-1)+1=x-1
f(-1)=e^2+1
f(-1)=7.389+1
f(-1) = 8.389
This question is from textbook
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
I'm assuming that the function is .
Evaluating f(-1):
Start with the given equation.
Plug in .
Multiply -2 and -1 to get 2.
Raise "e" to the 2nd power to get 7.3891 (note: this value is approximate).
Add 1 to 7.3891 to get 8.3891.
----------------------------
Evaluating f(3):
Start with the given equation.
Plug in .
Multiply -2 and 3 to get -6.
Raise "e" to the -6th power to get 0.0025 (note: this value is approximate).
Add 1 to 0.0025 to get 1.0025.
----------------------------
Evaluating f(-2):
Start with the given equation.
Plug in .
Multiply -2 and -2 to get 4.
Raise "e" to the 4th power to get 54.5982 (note: this value is approximate).
Add 1 to 54.5982 to get 55.5982.
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