SOLUTION: solve each equation for x. 4+10^3-x=106 ln(x^2+x)=1

Question 189948: solve each equation for x.
4+10^3-x=106
ln(x^2+x)=1
Answer by cutepiscean5(19) (Show Source): You can put this solution on YOUR website!
Lets take the first equation:
4+10^3-x=106
I shall consider the given equation written as:

=>
=>
Taking log on both sides of the equation we get:
=>
using the log properties that: , we get:
=>
using log(10) = 1 and log(102) = 2.0086, we get:
=>
=>
=>

solving the second equation we get:
ln(x^2+x)=1
using the log property that if, , then , we get:

=>
Solving using the quadratic formula we get:

here , a = 1, b = 1 and c = -e
thus,

or,
, and

you can further simplify this by plugging in the value of e as 2.718, and solving. It depends on how the answer is required.

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