You can
put this solution on YOUR website! hi i have a question about a Logarithm problem
log(x-6)-log(x-2)=log x/5
i understand (X-6)/(X-2) = LOG X - LOG 5
""WHY DOES X GOES WITH (X-6) AND 5 GOES WITH (X-2)""""
so the problem goes something like this x(x-6)/5(x-2)=10^0 =1
x^2-6x=1*5(x-2) = which is x^2-11x-10=0
------------------
log(x-6)-log(x-2)=log x/5 Solve for x ?
log((x-6)/(x-2)) = log(x/5)
(x-6)/(x-2) = x/5
x*(x-2) = 5*(x-6)
| Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) |
Quadratic equation  (in our case  ) has the following solutons:
For these solutions to exist, the discriminant  should not be a negative number.
First, we need to compute the discriminant :  .
The discriminant -71 is less than zero. That means that there are no solutions among real numbers.
If you are a student of advanced school algebra and are aware about imaginary numbers, read on.
In the field of imaginary numbers, the square root of -71 is + or -  .
The solution is  , or
Here's your graph:
 |
-------------------
The logs of complex numbers is outside the scope of this forum.
