SOLUTION: log(2x^2+3x) = log(10x+30)

Question 187166: log(2x^2+3x) = log(10x+30)
Found 2 solutions by user_dude2008, uday1435:
Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
log(2x^2+3x) = log(10x+30)

2x^2+3x = 10x+30

2x^2+3x - 10x - 30 = 0

2x^2-7x-30 = 0

(x-6)(2x+5) = 0

x-6=0 or 2x+5=0

Ans: x=6 or x=-5/2

Answer by uday1435(57) (Show Source): You can put this solution on YOUR website!
log(2x^2+3x) = log(10x+30)
2x^3 + 3x = 10x +30
2x^3 � 7x � 30 = 0
(2x+5)(x � 6) = 0
So x = 6 or � (5/2)

If you still require further clarifications please write to udayakumar.t.r@gmail.com

RELATED QUESTIONS
log (2-3x) - log x = log... (answered by longjonsilver)
log(2x+1)-log(3x-2)=1 (answered by MathLover1)
Log(3x+1)+log(1/2)+log(2x-5)=0 (answered by MathLover1)
log(10x/y^2) (answered by tommyt3rd)
log 3x - 8 = log... (answered by Nate,ryanman)
log 10x - log (2x - 3) = log 7 solve for... (answered by stanbon)
I would greatly appreciate any help you can give me in working this problem - Question:... (answered by stanbon)
log(3x)= log 5 +... (answered by drk)
How do I solve Log(base 2)(10x) = Log(base... (answered by lwsshak3)