SOLUTION: Hi there, Could you please help me with the following advanced functions question? I tried really hard to get a solution, I just dont know how to solve it in a trial and error man

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Question 186256: Hi there,
Could you please help me with the following advanced functions question? I tried really hard to get a solution, I just dont know how to solve it in a trial and error manner.
Question: Use systematic trial and error to evaluate log50. (2 marks)
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
A log the the exponent you raise 10 to in order to obtain a specific vlaue.
So you know that 10%5E1 = 10
and {10^2))) = 100
So Log(50) is between 1 and 2
50 is a little less that halfway between 10 and 100. But logs are exponential. So try 1.5.
What is 10%5E%281.5%29 = 31.6
Try 1.75
10%5E%281.75%29 = 56.23
Sp it is close to 1.75, just a little less
Try 1.7
10%5E%281.7%29 = 50.11
That's close enough for me.
Log(50) = 1.699