SOLUTION: PLEASE HELP ME:) ALGEBRAICALLY Solve: 1) logbase7 x - 1/2 logbase7 9 = logbase7 5 2) 1/4 logbase5 81

SOLUTION: PLEASE HELP ME:) ALGEBRAICALLY Solve: 1) logbase7 x - 1/2 logbase7 9 = logbase7 5 2) 1/4 logbase5 81 - logbase5 x = logbase5 (x+2)

Question 186097: PLEASE HELP ME:)
ALGEBRAICALLY Solve:
1) logbase7 x - 1/2 logbase7 9 = logbase7 5
2) 1/4 logbase5 81 - logbase5 x = logbase5 (x+2)
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
logbase7 x - 1/2 logbase7 9 = logbase7 5
logbase7(x) = logbase7(5) + 1/2logbase7(9)

RELATED QUESTIONS
how to solve logbase7 (x+5)-logbase7 *3=logbase7... (answered by rothauserc)

Solve for x:... (answered by solver91311)

SOLVE Logbase5(1/25)=x (answered by nerdybill)

2logbase5(z)+... (answered by ewatrrr)

Solve: a) logbase5 6-logbase5 x=logbase5 2 b) logbase2 8-logbase2 4=x c) logbase3 27+... (answered by stanbon)

Solve: a) logbase3 27+ logbase3 9-logbase3 81= logbase3 x ( I think the answer is 3) b) (answered by vleith)

I keep messing up these, it's so confusing. Solve a)7^2x+1 = 4^x-2 b) 4^x = 3+18(4^-�) (answered by Alan3354)

Solve for x: a) (log base2 x)^2-(logbase2 x^2)=0 b) log base2(logbasex 64)=1 c) log... (answered by stanbon)

logbase5(x+2)+logbase5(x-1)=2?? I tried solving it but I don't know If I am write I did (answered by josgarithmetic)