SOLUTION: Log5(3x^2-1)=Log5(2x)

Question 176366This question is from textbook
: Log5(3x^2-1)=Log5(2x) This question is from textbook

Answer by EMStelley(208) (Show Source): You can put this solution on YOUR website!
Since both of the sides are log base 5, all that is needed is to set the arguments equal to each other:

I will use the quadratic formula to solve with a=3,b=-2, c=-1.

and

Now, with logarithms you always want to check your answer because you cannot take the log of a negative number. Notice that if you plugged in x=-1/3 to the right hand side (log5(2x)) you would be taking the log of a negative number. So x=-1/3 is what is called an extraneous solution. Therefore, x=1 is the only solution.
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