SOLUTION: I need to solve for x
25=5*10^(x/2)
I know I am supposed to use log to bring the x/2 down somehow but I just can't figure it out
Algebra.Com
Question 175542: I need to solve for x
25=5*10^(x/2)
I know I am supposed to use log to bring the x/2 down somehow but I just can't figure it out
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
I need to solve for x
25=5*10^(x/2)
Divide by 5
5 = 10^(x/2)
--------------
No problem so far, right?
Now take the log of both sides. Logs (base 10) are the exponents to which 10 is raised to get the number. Since the right side is already 10 to an exponent, the exponent is the log.
That is, the log of 10^anything is...anything. In this case, it's x/2.
-------------
log(5) = x/2
x = 2*log(5)
x = log(25)
x =~ 1.39794
RELATED QUESTIONS
{{{ log( 3,x ) }}} ^2 + {{{ log( 3,x^2) }}} -3 = 0
What is x?
Basically, this question (answered by josgarithmetic)
I am supposed to solve for x and the base of the logarithm is 10 but I can not figure it... (answered by stanbon)
Please help me solve. Thank you
(1-x)^2=9
I think that I am supposed to set it to... (answered by checkley77)
Please help me solve. Thank you
(1-x)^2=9
I think that I am supposed to set it to... (answered by checkley77,jsmallt9)
Hello, I am supposed to simplify this expression: (x^5/2*y^2)^-1/4
without any negative (answered by Alan3354)
If 3^(2x) + 9 = 10(3^x) solve for x.
I know that x = 2 but only because of guess an... (answered by Fombitz)
Solve the equation.
logbase6(x − 5) + logbase6(x) = 2
I know you can bring them (answered by stanbon)
Solve for x using logs.
2^x=e^(x+5)
I know im supposed to use ln, but I get stuck... (answered by John10)
I am trying to figure out how to simplify and hence solve the following equation.... (answered by khwang)