SOLUTION: I need the help on Log Use the properties of logarithms to find the exact value of the expression. log 21-log 7 the 3's are lower by the G's like an exponent but bottom...

Question 175313: I need the help on Log
Use the properties of logarithms to find the exact value of the expression.
log 21-log 7 the 3's are lower by the G's like an exponent but bottom...
3 3
I came up with the answer 1 is that correct?
log(4+x)-log(x-5)=log2 I cant find the answer as well.Uhgg
I do not have these in my book...Help
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
The subscript next to log specifies the "base".
.
log_3(21)- log_3(7)
applying "log rules":
log_3(21)- log_3(7) = log_3(21/7) = log_3(3) = 1
Note: since 3^1 = 3
.
log(4+x)-log(x-5)=log2
log((4+x)/(x-5))=log2
(4+x)/(x-5) = 2
(4+x) = 2(x-5)
4+x = 2x-10
4 = x-10
14 = x
.
To review log rules see:
http://www.purplemath.com/modules/logrules.htm

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