SOLUTION: the e is the base LOGe (-.3675) thanks

Algebra.Com
Question 175032: the e is the base
LOGe (-.3675)
thanks

Answer by user_dude2008(1862)   (Show Source): You can put this solution on YOUR website!
LOGe (-.3675) = ln(-.3675)= UNDEFINED

Can't do it since the log of a negative # is undefined

RELATED QUESTIONS

Evaluate the expression loge(1/e^2) (answered by stanbon)
Find the exact value of e^LOGe^2 16 The answer is 4, but I am unsure as to why. If... (answered by addingup)
what is the domain of the function... (answered by solver91311)
Given x > 1, solve for x (log x^7)(log x) − log x^2 − 5 = 0 I had x =... (answered by josgarithmetic)
loge(base... (answered by ewatrrr)
Please help me solve for A and B in this exponential decay model y= ae^-bx. I have the... (answered by jsmallt9)
The two right circular cones are similar. The height of the larger cone is 80 cm, and the (answered by MathLover1)
find x if logeX + loge3 = 1 the "e" in problem is the base.... (answered by bucky)
Rewrite each of the following as an equivalent exponential equation.Do not solve. loge... (answered by stanbon,Alan3354)