SOLUTION: Given that log_3x=2 and log_3y=5, evaluate:
log_3 ((27(x^-2)y)
Algebra.Com
Question 174939: Given that log_3x=2 and log_3y=5, evaluate:
log_3 ((27(x^-2)y)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Given that log_3x=2 and log_3y=5, evaluate:
log_3 ((27(x^-2)y)
----------------
Problem:
log_3 ((27(x^-2)y) = log3 (27) -2log3 (x) + log3 (y)
= 3 -2(2) + 5
= -4
============
Cheers,
Stan H.
RELATED QUESTIONS
Given that log x = 3.7 and log y = 3, evaluate
log (x^2 y^3)
(answered by Theo)
Given that log x = 5.5 and log y = 1.7, evaluate
log (x^2... (answered by reviewermath)
given log b 2= 0.3562, log b 3=0.5646, log b 5=0.8271 and log b 11=1.2323
evaluate:... (answered by vleith)
log (x^2)(y) - .5 log x + 3 log... (answered by ccs2011)
log (6x + 5) - log 3 = log 2 - log x
(answered by rapaljer,arunpaul)
log(3x)= log 5 +... (answered by drk)
Given log 2 = 0.3010 and log 3 = 0.4771
What is log 8/27
Thank you... (answered by MathLover1)
if log base b (2)=x and log base b (3)=y, evaluate the following terms of x and y:
log (answered by stanbon)
evaluate log 2(y -3) + log 4 base 2... (answered by lwsshak3)
{{{ (Log( x, x^4 ) - Log( 3, 27 )) / (Log( .01 ) + Log( 4, 2 )) }}} Solve for... (answered by stanbon)