SOLUTION: Hello, My question concerns growth, but I do not understand how to use the log in the equation. It reads f(x)=400 log10 (2t+3). It is asking how many animals will there be after

Question 173741: Hello,
My question concerns growth, but I do not understand how to use the log in the equation. It reads f(x)=400 log10 (2t+3). It is asking how many animals will there be after six months. Can you help me make sense of this problem? Thank you ever so much.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
My question concerns growth, but I do not understand how to use the log in the equation. It reads f(x)=400 log10 (2t+3). It is asking how many animals will there be after six months.
:
Assume you mean log,base10, which can just be written log( ), so we have
f(t) = 400*log(2t+3)
:
Find f(t) when t = 6
f(t) = 400 * log[2(6) + 3]
;
f(t) = 400 * log(12 + 3)
:
f(t) = 400 * log(15)
:
Find the log of 15
f(t) = 400 * 1.1761
:
f(t) = 470 animals after 6 months
:
Hope this is what you mean.
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