SOLUTION: 1/3logbX + 3logbY - 4logbX =
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Question 172588: 1/3logbX + 3logbY - 4logbX =
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
1/3logbX + 3logbY - 4logbX =
= log(x^(1/3)) + log(y^3) - log(x^4) (all the same base)
= log(y^3*x^(1/3)/x^4)
=
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