SOLUTION: Please solve log base 2^(x-2)=logbase2^(x-4)
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Question 172077: Please solve log base 2^(x-2)=logbase2^(x-4)
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Please solve log base 2^(x-2)=logbase2^(x-4)
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I don't understand what you mean. Pls clarify.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve log base 2^(x-2)=logbase2^(x-4)
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log2 sqrt(x-2)- log2 sqrt(x-4) = 0
= log2[sqrt(x-2)/sqrt(x-4)] = 0
= sqrt[(x-2)/(x-4)] = 2^0
Square both sides to get:
[(x-2)/(x-4)] [(x-2)/(x-4)] =1
x-2 = x-4
-2 = -4
A contradiction.
No solution for the original equation.
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Cheers,
Stan H.
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