SOLUTION: what would log3 28 be and use log6 3= 0.1613147 and log6 5=0.898244 to find log6 45.

Question 171594: what would log3 28 be and use log6 3= 0.1613147 and log6 5=0.898244 to find log6 45.
Found 2 solutions by Alan3354, nerdybill:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
what would log3 28 be
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(or log base 10, just so they match)
=~ 3.0331
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and use log6 3= 0.1613147 and log6 5=0.898244 to find log6 45.
45 = 3*3*5

or it would if
It doesn't.

That makes the

Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
what would log3 28 be
log3 28 = log(28)/log(3) = 1.4472/0.4771 = 0.6905
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use log6 3= 0.1613147 and log6 5=0.898244 to find log6 45.
since we can rewrite
log6 45 = log6(5*3*3)
log6 45 = log6(5) + log6(3) + log6(3)
log6 45 = 0.898244 + 0.1613147 + 0.1613147 = 1.2208734

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