SOLUTION: It asks to write it in condensed form:
logb 3 x + 8(logb x - logb y)
1/2loga x + 4 loga y - 4 log a x
Algebra.Com
Question 171237: It asks to write it in condensed form:
logb 3 x + 8(logb x - logb y)
1/2loga x + 4 loga y - 4 log a x
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
logb 3 x + 8(logb x - logb y)
= logb3x + 8(log(x/y)
= logb[3x*(x/y)^8]
= logb[3(x^9/y)]
============================
1/2loga x + 4 loga y - 4 log a x
= loga (x^(1/2) + loga(y^4) - loga(x^4)
= loga[x^(1/2)*y^4/x^4]
= loga[y^4/x^(7/2)]
===========================
Cheers,
Stan H.
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