SOLUTION: Solve: log(x+7)=1-logx

Algebra.Com
Question 170477: Solve:
log(x+7)=1-logx

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
log(x+7)=1-logx
log[x(x+7)] = 1
x^2+7x=10
x^2+7x-10 = 0
x = [-7 +- sqrt(7^2 -4*-10)]/2
x = [-7 +- sqrt(89)]/2
Positive solution:
x = [-7 + sqrt(89)]/2
x = 1.216991
=================
Cheers,
Stan H.

RELATED QUESTIONS

solve: logx + log(x-3) = 1 (answered by jsmallt9)
solve {{{ log(x+9)+logx=1... (answered by ewatrrr)
solve: logx + log(x+3)=... (answered by nerdybill)
Solve log(x-1)- log6 = log(x-2)-... (answered by HyperBrain)
solve for x .... (answered by stanbon)
log(x+3)=1-logx (answered by josmiceli)
logx-log(x-1)=2 (answered by user_dude2008)
log(x+3)=1-logx (answered by drk)