SOLUTION: Solve:
log(x+7)=1-logx
Algebra.Com
Question 170477: Solve:
log(x+7)=1-logx
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log(x+7)=1-logx
log[x(x+7)] = 1
x^2+7x=10
x^2+7x-10 = 0
x = [-7 +- sqrt(7^2 -4*-10)]/2
x = [-7 +- sqrt(89)]/2
Positive solution:
x = [-7 + sqrt(89)]/2
x = 1.216991
=================
Cheers,
Stan H.
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