SOLUTION: Could you help me solve this equation?
2-log3x = log(x/12)
How do you know?
Thank you so much.
Algebra.Com
Question 169505This question is from textbook Exponential and Logarithmic Equations and Inequalities
: Could you help me solve this equation?
2-log3x = log(x/12)
How do you know?
Thank you so much.
This question is from textbook Exponential and Logarithmic Equations and Inequalities
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
2-log3x = log(x/12)
log(x/12) + log(3x) = 2
log[x^2/4] = 2
x^2/4 = 10^2
x^2 = 400
Positive solution:
x = +20
===============
Cheers,
Stan H.
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