SOLUTION: log5x=log4+log(x+1)
Algebra.Com
Question 169108: log5x=log4+log(x+1)
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
You will need to apply "log rules". For a refresher see:
http://www.purplemath.com/modules/logrules.htm
.
log5x=log4+log(x+1)
log5x=log(4(x+1))
log5x=log(4x+4)
5x=4x+4
x=4
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