SOLUTION: need to solve for x. problem : log6(4x+1)=2

Question 167833: need to solve for x. problem : log6(4x+1)=2
Found 2 solutions by stanbon, Earlsdon:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
need to solve for x. problem : log6(4x+1)=2
------------
4x+1 = 6^2
4x = 35
x = 35/4
============
Cheers,
Stan H.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Use the fact that:
means
means so...
Subtract 1 from both sides.
Divide both sides by 4.

RELATED QUESTIONS
Please help me to solve this problem: log6(t+1)-log6(t^2-1)... (answered by lwsshak3)
log6(15-x)+log6(x)=2 solve for... (answered by Alan3354)
Solve Log6(x+3) + Log6(x-2) = 1 * 6 is the base for both logs (answered by user_dude2008)
Solve for x Log6(x) = log6(36) - log6(1/6) please explain and show work... (answered by josmiceli,stanbon)
log6(x-1)+log6(x+4)=2 (answered by nerdybill)
Hi I couldnt figure out how to do this problem... (answered by stanbon)
2+log6(x-1)=log6(12x) (answered by Fombitz)
Solve for x in the equation log6(2x + 8) − log6(x + 1) =... (answered by jsmallt9)
Using the exponential correlation, how do I solve for x. Round to three decimal places.... (answered by lwsshak3)