SOLUTION: Can you please help me solve this? log3(3x^2+21x)+log3(x+2)=log3(25x^2+90x+32)

Question 167756: Can you please help me solve this?
log3(3x^2+21x)+log3(x+2)=log3(25x^2+90x+32)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log3(3x^2+21x)+log3(x+2)=log3(25x^2+90x+32)
-------------------------
log3[(3x^2+21x)(x+2)] = log3(25x^2+90x+32)

[(3x^2+21x)(x+2)] = (25x^2+90x+32)
3x^3 + 6x^2 + 21x^2 + 42x = 25x^2 + 90x + 32
3x^3 + 27x^2 + 42x = 25x^2 + 90x + 32
3x^3 + 2x^2 - 48x - 32 = 0
==================
x=-4 or x = -2/3 or x = 4
================
Cheers,
Stan H.
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