SOLUTION: log base 6 (3x-2) + log base 6 (x-3)=1
i worked out this problem, and got an incorrect answer.
Algebra.Com
Question 167210: log base 6 (3x-2) + log base 6 (x-3)=1
i worked out this problem, and got an incorrect answer.
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
using rules for logs __ (3x-2)(x-3)=6
3x^2-11x+6=6 __ 3x^2-11x=0 __ x(3x-11)=0
x=0 __ not realistic __ logs are not defined for negative values
3x-11=0 __ x=11/3
RELATED QUESTIONS
please help me solve this equation;
log(base 6)3x + log(base 6)(x-1) = 3
(answered by nerdybill)
Please help:
I have solved this, but I'm unsure if it's right.
------------------
1/2... (answered by lwsshak3)
In(2x)=5
log base 5(8-3x)= 0.75
log base 4[(3x + 8)(x-6)] =3
log base 2 (x-7) +... (answered by addingup)
This one looked easy but it's got me confused please help and thank you.
Use the laws of (answered by josmiceli)
how do i solve a problem like this
log base 6 3/50
log base 6 10=1.3
log base 6... (answered by Alan3354)
Solve: log base 2 (3x+6)- log base 2 (x-5)= log base 2... (answered by Nate)
solve
1/2 log 25 base 6 + log x base 6 = log 20 base... (answered by solver91311,lwsshak3)
solve this logarithmic equation & give the exact answer.
log(base)3 (x+6) + log(base)3 (answered by nerdybill)
find x if log 6 base 3 + log x base 3 - log 5 base... (answered by lwsshak3)