SOLUTION: log^2 (x^2-6x) = 3+log^2(1-x)

Question 166780: log^2 (x^2-6x) = 3+log^2(1-x)
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
I'm assuming when you say log^2, you mean log base 2.
If not, please write back.
.
log2(x^2-6x) = 3+log2(1-x)
log2(x^2-6x) - log2(1-x) = 3
log2[(x^2-6x)/(1-x)] = 3
(x^2-6x)/(1-x) = 2^3
(x^2-6x)/(1-x) = 8
(x^2-6x) = 8(1-x)
x^2-6x = 8-8x
x^2+2x = 8
x^2+2x-8 = 0
(x+4)(x-2) = 0
.
x = {-4, 2}

RELATED QUESTIONS
log (6x + 5) - log 3 = log 2 - log x (answered by rapaljer,arunpaul)

Log(6x-1)+ log x= 1/2 log... (answered by Gogonati)

Log(x+2) - log(x-1) = logx -... (answered by ewatrrr)

log(X+3)-log X=log... (answered by Fombitz)

log(x-3)+log(2)=1 (answered by fractalier)

1/2 log... (answered by edjones)

please help me solve this log (6x+5) - log (3) = log (2) - log... (answered by solver91311)

Log 3... (answered by ewatrrr)

log(log(x))=2 (answered by Edwin McCravy,stanbon)