SOLUTION: 3(5)^(-.01x)=6

Question 166775: 3(5)^(-.01x)=6
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
3(5)^(-.01x)=6
(5)^(-.01x)=2
-.01x=log5(2)
-.01x=log(2)/log(5)
-.01x=.4307
x = -43.068
.
Note:
log5 : log base 5
log : (w/o any number) means log base 10
.
This is a good site to review log rules:
http://www.purplemath.com/modules/logrules.htm

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