SOLUTION: log(x+8)+ log(x-1)=1 not quite sure how to do this. My guess is to distribute the log then solve for x.

SOLUTION: log(x+8)+ log(x-1)=1 not quite sure how to do this. My guess is to distribute the log then solve for x.

Algebra.Com

Question 166760: log(x+8)+ log(x-1)=1
not quite sure how to do this. My guess is to distribute the log then solve for x.
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!

x=-9 or x=2
Sub back into the original equation to find the value(s) that work
Log of a negative number is not defined, so only x=2 works

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